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In alternating current (AC, also ac), the movement of electric charge periodically reverses direction. In direct current (DC, also dc), the flow of electric charge is only in one direction. The abbreviations AC and DC are often used to mean simply alternating and direct, as when they modify current or voltage. AC is the form in which electric power is delivered to businesses and residences. The usual waveform of an AC power circuit is a sine wave. In certain applications, different waveforms are used, such as triangular or square waves. Audio and radio signals carried on electrical wires are also examples of alternating current. In these applications, an important goal is often the recovery of information encoded (or modulated) onto the AC signal. From Wikipedia under the
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GNU Free Documentation License ) www.labx.com 265 x 265px [source page] Used prater hammermill, blue streak, MODEL B- 9AC , carbon ste From Google Image Search: "9ac" 3 min., 26 sec. www.youtube.com Thu, 03 Nov 2011 08:26:33 PDT From Google Video Search: "9ac" Answers to these questions? Q. Factorize: 10+6d 10c+12d 18ax-15ay 20mn+30mp 54gh-6h 10c+14e+8e 5ax-15ay-30a 6p-24p-12qr a(9c-4)+2b(9c-4) 3w(y+2x)+(2x+y) ax+bx+ay+by 2x+xy+yz+2z 9ac-4a+18bc-8 2+8k-3-12km 1+4k-m-4km Asked by Kaili - Tue Mar 8 19:20:34 2011 - Mathematics - 2 Answers - Comments A. 2(5+3d) 2(5c+6d) 3a(6x-5y) 10m(2n+3p) 6h(9g-1) 2(5c+7e+4e) = 2(5c+11e) 5a(x-3y-6a) 6(p-4p-2qr) (a+2b)(9c-4) (3w+1)+(2x+y) x(a+b)+y(a+b) = (x+y)(a+b) x(2+y)+z(2+y) = (x+z)(2+y) ?? is it supposed to be [9ac-4a+18bc-8b] then a(9c-4)+2b(9c-4) = (a+2b)(9c-4) 2(1+4k)-3(1+4k) = (2-3)(1+4k) = -1(1-4k) = -1+4k 1(1+4k)-m(1+4k) = (1-m)(1+4k) Answered by Elliot - Tue Mar 8 19:39:53 2011 How do I factor by grouping this?
Q. 3x^2y-6x^2-2y+y^2 and 4ab^2-12a^2b-3bc+9ac Asked by Shanna Hunter - Sun Jun 13 12:21:31 2010 - Homework Help - 1 Answers - Comments A. 1.ok so first you have to see what you can group together. 3x^2y-6x^2-2y+y^2 -here, you can simply group first two and last two pairs together 3x^2(y-2)+y(-2+y) - here we have, (-2+y) we can also write that as (y-2), now we have a common factor: (3x^2+y)(y-2) 2.Also, first you have to see what can be grouped: 4ab^2-12a^2b-3bc+9ac - again, we can group first two and last two pairs 4ab(b-3a)-3c(b-3a) - because (-3c)*(-3a)=(+)9ac (4ab-3c)(b-3a) Answered by I Just Know - Sun Jun 13 13:02:06 2010 From Yahoo Answer Search: "9ac" |
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